Optimal. Leaf size=129 \[ -\frac{1}{2} \text{PolyLog}\left (2,\frac{2}{a x+1}-1\right )-\frac{11 a x}{32 \left (1-a^2 x^2\right )}-\frac{a x}{16 \left (1-a^2 x^2\right )^2}+\frac{\tanh ^{-1}(a x)}{2 \left (1-a^2 x^2\right )}+\frac{\tanh ^{-1}(a x)}{4 \left (1-a^2 x^2\right )^2}+\frac{1}{2} \tanh ^{-1}(a x)^2-\frac{11}{32} \tanh ^{-1}(a x)+\log \left (2-\frac{2}{a x+1}\right ) \tanh ^{-1}(a x) \]
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Rubi [A] time = 0.249641, antiderivative size = 129, normalized size of antiderivative = 1., number of steps used = 12, number of rules used = 7, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.35, Rules used = {6030, 5988, 5932, 2447, 5994, 199, 206} \[ -\frac{1}{2} \text{PolyLog}\left (2,\frac{2}{a x+1}-1\right )-\frac{11 a x}{32 \left (1-a^2 x^2\right )}-\frac{a x}{16 \left (1-a^2 x^2\right )^2}+\frac{\tanh ^{-1}(a x)}{2 \left (1-a^2 x^2\right )}+\frac{\tanh ^{-1}(a x)}{4 \left (1-a^2 x^2\right )^2}+\frac{1}{2} \tanh ^{-1}(a x)^2-\frac{11}{32} \tanh ^{-1}(a x)+\log \left (2-\frac{2}{a x+1}\right ) \tanh ^{-1}(a x) \]
Antiderivative was successfully verified.
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Rule 6030
Rule 5988
Rule 5932
Rule 2447
Rule 5994
Rule 199
Rule 206
Rubi steps
\begin{align*} \int \frac{\tanh ^{-1}(a x)}{x \left (1-a^2 x^2\right )^3} \, dx &=a^2 \int \frac{x \tanh ^{-1}(a x)}{\left (1-a^2 x^2\right )^3} \, dx+\int \frac{\tanh ^{-1}(a x)}{x \left (1-a^2 x^2\right )^2} \, dx\\ &=\frac{\tanh ^{-1}(a x)}{4 \left (1-a^2 x^2\right )^2}-\frac{1}{4} a \int \frac{1}{\left (1-a^2 x^2\right )^3} \, dx+a^2 \int \frac{x \tanh ^{-1}(a x)}{\left (1-a^2 x^2\right )^2} \, dx+\int \frac{\tanh ^{-1}(a x)}{x \left (1-a^2 x^2\right )} \, dx\\ &=-\frac{a x}{16 \left (1-a^2 x^2\right )^2}+\frac{\tanh ^{-1}(a x)}{4 \left (1-a^2 x^2\right )^2}+\frac{\tanh ^{-1}(a x)}{2 \left (1-a^2 x^2\right )}+\frac{1}{2} \tanh ^{-1}(a x)^2-\frac{1}{16} (3 a) \int \frac{1}{\left (1-a^2 x^2\right )^2} \, dx-\frac{1}{2} a \int \frac{1}{\left (1-a^2 x^2\right )^2} \, dx+\int \frac{\tanh ^{-1}(a x)}{x (1+a x)} \, dx\\ &=-\frac{a x}{16 \left (1-a^2 x^2\right )^2}-\frac{11 a x}{32 \left (1-a^2 x^2\right )}+\frac{\tanh ^{-1}(a x)}{4 \left (1-a^2 x^2\right )^2}+\frac{\tanh ^{-1}(a x)}{2 \left (1-a^2 x^2\right )}+\frac{1}{2} \tanh ^{-1}(a x)^2+\tanh ^{-1}(a x) \log \left (2-\frac{2}{1+a x}\right )-\frac{1}{32} (3 a) \int \frac{1}{1-a^2 x^2} \, dx-\frac{1}{4} a \int \frac{1}{1-a^2 x^2} \, dx-a \int \frac{\log \left (2-\frac{2}{1+a x}\right )}{1-a^2 x^2} \, dx\\ &=-\frac{a x}{16 \left (1-a^2 x^2\right )^2}-\frac{11 a x}{32 \left (1-a^2 x^2\right )}-\frac{11}{32} \tanh ^{-1}(a x)+\frac{\tanh ^{-1}(a x)}{4 \left (1-a^2 x^2\right )^2}+\frac{\tanh ^{-1}(a x)}{2 \left (1-a^2 x^2\right )}+\frac{1}{2} \tanh ^{-1}(a x)^2+\tanh ^{-1}(a x) \log \left (2-\frac{2}{1+a x}\right )-\frac{1}{2} \text{Li}_2\left (-1+\frac{2}{1+a x}\right )\\ \end{align*}
Mathematica [A] time = 0.200269, size = 81, normalized size = 0.63 \[ \frac{1}{128} \left (-64 \text{PolyLog}\left (2,e^{-2 \tanh ^{-1}(a x)}\right )+64 \tanh ^{-1}(a x)^2-24 \sinh \left (2 \tanh ^{-1}(a x)\right )-\sinh \left (4 \tanh ^{-1}(a x)\right )+4 \tanh ^{-1}(a x) \left (32 \log \left (1-e^{-2 \tanh ^{-1}(a x)}\right )+12 \cosh \left (2 \tanh ^{-1}(a x)\right )+\cosh \left (4 \tanh ^{-1}(a x)\right )\right )\right ) \]
Warning: Unable to verify antiderivative.
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Maple [B] time = 0.063, size = 234, normalized size = 1.8 \begin{align*}{\frac{{\it Artanh} \left ( ax \right ) }{16\, \left ( ax-1 \right ) ^{2}}}-{\frac{5\,{\it Artanh} \left ( ax \right ) }{16\,ax-16}}-{\frac{{\it Artanh} \left ( ax \right ) \ln \left ( ax-1 \right ) }{2}}+{\it Artanh} \left ( ax \right ) \ln \left ( ax \right ) +{\frac{{\it Artanh} \left ( ax \right ) }{16\, \left ( ax+1 \right ) ^{2}}}+{\frac{5\,{\it Artanh} \left ( ax \right ) }{16\,ax+16}}-{\frac{{\it Artanh} \left ( ax \right ) \ln \left ( ax+1 \right ) }{2}}-{\frac{{\it dilog} \left ( ax \right ) }{2}}-{\frac{{\it dilog} \left ( ax+1 \right ) }{2}}-{\frac{\ln \left ( ax \right ) \ln \left ( ax+1 \right ) }{2}}-{\frac{ \left ( \ln \left ( ax-1 \right ) \right ) ^{2}}{8}}+{\frac{1}{2}{\it dilog} \left ({\frac{1}{2}}+{\frac{ax}{2}} \right ) }+{\frac{\ln \left ( ax-1 \right ) }{4}\ln \left ({\frac{1}{2}}+{\frac{ax}{2}} \right ) }+{\frac{ \left ( \ln \left ( ax+1 \right ) \right ) ^{2}}{8}}-{\frac{1}{4} \left ( \ln \left ( ax+1 \right ) -\ln \left ({\frac{1}{2}}+{\frac{ax}{2}} \right ) \right ) \ln \left ( -{\frac{ax}{2}}+{\frac{1}{2}} \right ) }-{\frac{1}{64\, \left ( ax-1 \right ) ^{2}}}+{\frac{11}{64\,ax-64}}+{\frac{11\,\ln \left ( ax-1 \right ) }{64}}+{\frac{1}{64\, \left ( ax+1 \right ) ^{2}}}+{\frac{11}{64\,ax+64}}-{\frac{11\,\ln \left ( ax+1 \right ) }{64}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 0.998892, size = 362, normalized size = 2.81 \begin{align*} \frac{1}{64} \, a{\left (\frac{2 \,{\left (11 \, a^{3} x^{3} + 4 \,{\left (a^{4} x^{4} - 2 \, a^{2} x^{2} + 1\right )} \log \left (a x + 1\right )^{2} - 8 \,{\left (a^{4} x^{4} - 2 \, a^{2} x^{2} + 1\right )} \log \left (a x + 1\right ) \log \left (a x - 1\right ) - 4 \,{\left (a^{4} x^{4} - 2 \, a^{2} x^{2} + 1\right )} \log \left (a x - 1\right )^{2} - 13 \, a x\right )}}{a^{5} x^{4} - 2 \, a^{3} x^{2} + a} + \frac{32 \,{\left (\log \left (a x - 1\right ) \log \left (\frac{1}{2} \, a x + \frac{1}{2}\right ) +{\rm Li}_2\left (-\frac{1}{2} \, a x + \frac{1}{2}\right )\right )}}{a} - \frac{32 \,{\left (\log \left (a x + 1\right ) \log \left (x\right ) +{\rm Li}_2\left (-a x\right )\right )}}{a} + \frac{32 \,{\left (\log \left (-a x + 1\right ) \log \left (x\right ) +{\rm Li}_2\left (a x\right )\right )}}{a} - \frac{11 \, \log \left (a x + 1\right )}{a} + \frac{11 \, \log \left (a x - 1\right )}{a}\right )} - \frac{1}{4} \,{\left (\frac{2 \, a^{2} x^{2} - 3}{a^{4} x^{4} - 2 \, a^{2} x^{2} + 1} + 2 \, \log \left (a^{2} x^{2} - 1\right ) - 2 \, \log \left (x^{2}\right )\right )} \operatorname{artanh}\left (a x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (-\frac{\operatorname{artanh}\left (a x\right )}{a^{6} x^{7} - 3 \, a^{4} x^{5} + 3 \, a^{2} x^{3} - x}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} - \int \frac{\operatorname{atanh}{\left (a x \right )}}{a^{6} x^{7} - 3 a^{4} x^{5} + 3 a^{2} x^{3} - x}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int -\frac{\operatorname{artanh}\left (a x\right )}{{\left (a^{2} x^{2} - 1\right )}^{3} x}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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